Знаходження первісних

$F\left(x\right)=x^5$

$F\left(x\right)=5x^4$

$F\left(x\right)=\frac{x^6}{6}+2$

$F\left(x\right)=\frac{x^4}{4}-2$

$F\left(x\right)=\sin x$

$F\left(x\right)=1+\sin x$

$F\left(x\right)=x^2+\cos x+C$

$F\left(x\right)=\frac{x^2}{2}+\sin x+C$

$F\left(x\right)=1+\sin x+C$

$F\left(x\right)=-\ln\left\vert x\right\vert+7x+C$

$F\left(x\right)=\ln\left\vert x\right\vert+7x+C$

$F\left(x\right)=-\frac{1}{x^2}+C$

$F\left(x\right)=\ln\left\vert x\right\vert+C$

$F\left(x\right)=\left\vert\ln x\right\vert+7x+C$

$F\left(x\right)=\frac{1}{x}+2\cos x+C$

$F\left(x\right)=-\frac{1}{x}+2\cos x+C$

$F\left(x\right)=-\frac{1}{x}-2\cos x+C$

$F\left(x\right)=\frac{1}{x^3}-2\cos x+C$

$F\left(x\right)=-\frac{1}{x}+2\cos x$

$F\left(x\right)=2\sqrt{x}-2\tg x+C$

$F\left(x\right)=4\sqrt{x}+2\tg x+C$

$F\left(x\right)=4\sqrt{x}+\frac{6}{\cos^3x}+C$

$F\left(x\right)=2\sqrt{x}+2\ctg x+C$

$F\left(x\right)=4\sqrt{x}-2\tg x+C$

$F\left(x\right)=\frac{1}{7x^2}+C$

$F\left(x\right)=\frac17\ln\left\vert x\right\vert+C$

$F\left(x\right)=7\ln\left\vert x\right\vert+C$

$F\left(x\right)=\ln\left\vert7x\right\vert+C$

$F\left(x\right)=-\frac{1}{7x^2}+C$

$F\left(x\right)=\left(\frac14x-1\right)^4$

$F\left(x\right)=\left(\frac14x-1\right)^4+1$

$F\left(x\right)=\left(\frac14x-1\right)^4+3$

$F\left(x\right)=\frac14\left(\frac14x-1\right)^4+2\frac34$

$F\left(x\right)=\frac34\left(\frac14x-1\right)^2$

$F\left(x\right)=-2e^{-2x}+C$

$F\left(x\right)=e^{-2x}+C$

$F\left(x\right)=-\frac12e^{-2x}+C$

$F\left(x\right)=\frac12e^{-2x}+C$

$F\left(x\right)=2e^{-2x}+C$

$-18\sin\frac{x}{3}\cos\frac{x}{3}+C$

$-\frac29\sin\frac{x}{3}\cos\frac{x}{3}+C$

$-\frac23\cos\frac23x+C$

$-\frac32\cos\frac23x+C$

$\frac32\cos\frac23x+C$

$\frac{2^{\frac{x}{2}}}{\ln2}+C$

$2\cdot\frac{2^{\frac{x}{2}}}{\ln2}$

$\frac{2^{\frac{x}{2}}}{2\ln2}+C$

$\frac{2^{\frac{x}{2}+1}}{\ln2}+C$

$\frac{2^{x}}{\ln2}+C$